Today we did a super cool expriment on Limiting Reactant and Percent Yield in a precipitation reaction. Our objective is ofcourse to first observe the reaction in the double replace ment reaction
Na2Co39(aq)+CaCl2(aq)------->NaCl(aq) + CaCO3(S). Then we determine the limiting reactant and the excess reactant. At the end will will than classify the Percent Yield by comparing our product produce in this experiment and the theoritical product.
Procedure:
1. In the begining of the lab we put on our safety equipments.
2. We obtain Na2Co3 solutions and CaCl2 solution and record our measurements.
3. Than we poor both sultions into a beaker and leave it sit for 5min
4. Than we write our name on a filter paper and set up the filter apparatus like this
5. We then place grducated cylinder underneath the funnel to start filtering.
6. We will use a wash bottle to rinse any NaCl left on the filter paper so that only the precipatate remains.
7. At the end we remove the filter paper with the precipitate CaCO3 into a dry location so that we can measure the percent yiled next class.
End of the Lab
With the double replacement balanced equation 1Na2CO3(aq)+1CaCl2(aq)------->1NaCl(aq) + 1CaCO3(S) we can find the limiting reactant. To find the limiting reactant, we simply just convert one reactant to another to see if they exceed more they are presented or the Presented is more than it is needed
E.g we use (25ml) of 0.70M Na2CO3 and (25ml) of 0.50M of CaCl2. In the end we converted them into moles. 0.018mol Na2CO3 and 0.012mol CaCl2.
0.0125molCaCl2* molNaCO3/molCaCl2=0.0125mol CaCl2. Thus CaCl2 is the limiting since it needs more than it is given.
Conclusion
To find the percent yield of this experiment, we will need to weigh the mass of the filter product which is next class. The formula to find the percent yied is
Na2Co39(aq)+CaCl2(aq)------->NaCl(aq) + CaCO3(S). Then we determine the limiting reactant and the excess reactant. At the end will will than classify the Percent Yield by comparing our product produce in this experiment and the theoritical product.
Procedure:
1. In the begining of the lab we put on our safety equipments.
2. We obtain Na2Co3 solutions and CaCl2 solution and record our measurements.
3. Than we poor both sultions into a beaker and leave it sit for 5min
4. Than we write our name on a filter paper and set up the filter apparatus like this
5. We then place grducated cylinder underneath the funnel to start filtering.
6. We will use a wash bottle to rinse any NaCl left on the filter paper so that only the precipatate remains.
7. At the end we remove the filter paper with the precipitate CaCO3 into a dry location so that we can measure the percent yiled next class.
End of the Lab
With the double replacement balanced equation 1Na2CO3(aq)+1CaCl2(aq)------->1NaCl(aq) + 1CaCO3(S) we can find the limiting reactant. To find the limiting reactant, we simply just convert one reactant to another to see if they exceed more they are presented or the Presented is more than it is needed
E.g we use (25ml) of 0.70M Na2CO3 and (25ml) of 0.50M of CaCl2. In the end we converted them into moles. 0.018mol Na2CO3 and 0.012mol CaCl2.
0.0125molCaCl2* molNaCO3/molCaCl2=0.0125mol CaCl2. Thus CaCl2 is the limiting since it needs more than it is given.
Conclusion
To find the percent yield of this experiment, we will need to weigh the mass of the filter product which is next class. The formula to find the percent yied is
Percent Yield= actual mass produced (grams) x 100
theoretical mass produced (grams)
excellent
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